t=-4.9t^2+30t+3

Solution for t=-4.9t^2+30t+3 equation:

t=-4.9t^2+30t+3

We move all terms to the left:

t-(-4.9t^2+30t+3)=0

We get rid of parentheses

4.9t^2-30t+t-3=0

We add all the numbers together, and all the variables

4.9t^2-29t-3=0

a = 4.9; b = -29; c = -3;
Δ = b2-4ac
Δ = -292-4·4.9·(-3)
Δ = 899.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{899.8}}{2*4.9}=\frac{29-\sqrt{899.8}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{899.8}}{2*4.9}=\frac{29+\sqrt{899.8}}{9.8}
$